9cm
3 cm
ab is parallel to dc.
ad = 9 cm, dc = 3 cm. angle bcd = 35°
angle abd = 90°
calculate the size of angle bad.
give your answer correct to one decimal place.

∴ ∠BAD = (0.2044) = 11.8°

Step-by-step explanation:

i) AD = 9 cm

ii) DC = 3 cm

iii) ∠BCD = 35°

iv) Since AB is parallel to DC and ∠ABD = 90°  then we can conclude that ∠BDC = 90°.

v) = 0.6128      ∴ BD  = 3 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) =      ⇒     sin(∠ BAD ) = = 0.2044

     ∴ ∠BAD = (0.2044) = 11.8°

i cant see the graph

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°