When selcting from a set of 10 distinct integersif sampling is done with replacement, how many samples of 5 are possible

10⁵ = 100,000

Step-by-step explanation:

Data provided in the question:

Number of available choices = 10

for the sample of 5 i.e n = 5

Repetition is allowed

Thus,

Total samples of 5 that are possible = ( Number of available choices )ⁿ

thus,

Total samples of 5 that are possible = 10⁵

Hence,

The Total samples of 5 that are possible = 100,000

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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step-by-step explanation: