Find the appropriate percentile from a t-distribution for constructing the following confidence interval.
99% t-interval with n = 3.

9.9248

Step-by-step explanation:

We know that the critical t- value for confidence interval is a two-tailed value from the t-distribution table corresponding to degree of freedom (df = n-1 , where n is the sample size) and the significance level () .

The given confidence interval = 99%

⇒ Significance level =

Sample size : n=3

DEgree of freedom : df = n-1 = 2

Then, the  critical t- value for 99% confidence interval will be;

  [From t-distribution table]

Hence, the appropriate percentile from a t-distribution for constructing the 99% confidence interval with n = 3 is 9.9248.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

there is no points to select.

step-by-step explanation: