Mathematics, 25.01.2020 12:31 aaburto1515

Sacha spent
of his time in study hall on science homework and
of his time on math homework. which expression
can be used to determine how much more of the time in study hall sacha spent on math than on science?
o 0.58 -0.28
o 0.058 -0.028
0.625 - 0.25
0.625 -0.025

Answers: 2

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Answers

Answer from: adriannacomrosenbark

Question:

Sacha spent Two-eighths of his time in study hall on science homework and Five-eighths of his time on math homework. Which expression can be used to determine how much more of the time in study hall Sacha spent on math than on science?

The expression can be used to determine how much more of the time in study hall Sacha spent on math than on science is 0.625t - 0.25t or 0.375t

Solution:

Let "t" be the total time spent on homework(science + math)

Given that Sacha spent Two-eighths of his time in study hall on science homework

Time spent on science homework = Two-eighths of his time

$\text {Time spent on science homework }=\frac{2}{8} \times t=\frac{2 t}{8}$

Five-eighths of his time on math homework

Time spent on maths homework = Five-eighths of his time

$\text {Time spent on maths homework }=\frac{5}{8} \times t=\frac{5 t}{8}$

To find how much more time Sacha spent on maths than science, we have to find the difference between time spent on math and time spent on science

Time spent on maths than science = Time spent on maths homework - Time spent on sceince homework

$\text {Time spent on maths than science }=\frac{5 t}{8}-\frac{2 t}{8}\\\\\text {Time spent on maths than science }=0.625t-0.25t = 0.375t$

Thus the expression can be used to determine how much more of the time in study hall Sacha spent on math than on science is 0.625t - 0.25t or 0.375t

Answer from: Quest

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

Answer from: Quest

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

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Sacha spent
of his time in study hall on science homework and
of his time on math homewo...