If y varies directly with x when y=16 and x=2.1, what is the value of x when y=4
rounded to the nearest tenth

0.53

Step-by-step explanation:

From variation ,

y ∞ x 1

y = kx , where k is called the constants of proportionality and must be calculated first before proceeding.

substitute for the values in equation 2 ,below

y   = kx 2

16 = k2.1

k   = 16/2.1

Now to find the value of x, make x the subject of the formula in equation 2

x  = y/k

   = 4/ 16/2.1

   = 4 ÷ 16/2.1

   = 4 x 2.1/16

   = 2.1/4

   = 0.525

 ≅ 0.53

y=sec x is the correct answer

~batmans wife dun dun