When a plane flies into the wind, it can travel 3000 ml in 6 h . when it flies with the wind, it can travel the same distance in 5 h. find the rate of the plane in still air and the rate of the wind

Step-by-step explanation:

If p and w represent the speeds of the plane and wind, respectively, the speed into the wind is ...

  p - w = (3000 mi)/(6 h) = 500 mi/h

And, the speed with the wind is ...

  p + w = (3000 mi)/(5 h) = 600 mi/h

Adding these two equations gives us ...

  2p = 1100 mi/h

  p = 550 mi/h . . . . . . . divide by 2

Then the wind speed is ...

  w = 600 mi/h - p = (600 -550) mi/h

  w = 50 mi/h

The rate of the plane in still air is 550 mi/h; the rate of the wind is 50 mi/h.

Step-by-step explanation:

let speed of plane in still air =x

speed of wind=y

(x-y)6=3000

x-y=3000/6=500   ...(1)

(x+y)5=3000

x+y=3000/5=600   ...(2)

adding (1) and (2)

2x=1100

x=1100/2=550

550 +y=600

y=600-550=50

speed of plane in still air=550 m/hr

speed of wind=50 m/hr

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

answer: 414,377,008

step-by-step explanation:

just multiply it