Solve -(2)/(3)x > 8 or -(2)/(3)x < 4
a{x | -12 < x < -6}
b{x | x < -12 or x > -6}
c{x | x > -12 or x < -6}

Option B. {x | x < -12 or x > -6}

Step-by-step explanation:

we have

---> inequality A

Solve for x

Multiply by -3/2 both sides

Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so

The solution of the inequality A is the interval (-∞,-12)

----> inequality B

Solve for x

Multiply by -3/2 both sides

Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so

The solution of the inequality B is the interval (-6,∞)

therefore

The solution of the system

 or    is equal to

(-∞,-12) ∪ (-6,∞)

{x | x < -12 or x > -6}

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: