What the equation of a circle that has a center (-11, -8 ) and radius of 4

x² + y² + 22x + 16y + 169 = 0

Step-by-step explanation:

Equation of a circle with center (a,b) , and radius r i.e center is  not the origin

The equation becomes

( x - a )² + ( y - b )² = r² 1

a = -11, b = -8

[( x - (-11 )]²  +  [( y - (-8)]² = 4²

      ( x + 11 )² + ( y + 8 )² = 4²

Carry out expansion

x² + 22x + 121 +  y² + 16y + 64 = 16

Rearrange the expression,

x² + y² + 22x + 16y + 121 + 64 - 16 = 0

x² + y² + 22x + 16y + 169 = 0

The equation of the circle is

x² + y² + 22x + 16y + 169 = 0

l.jnl.j/n.m,lm,

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18