Acompany produces three combinations of mixed vegetables that sell in 1-kg packages. italian style combines 0.4

kg of zucchini, 0.3

kg of broccoli, and 0.3

kg of carrots. french style combines 0.5

kg of broccoli and 0.5

kg of carrots. oriental style combines 0.2

kg of zucchini, 0.3

kg of broccoli, and 0.5

kg of carrots. the company has a stock of 17 comma 800

kg of zucchini, 28 comma 300

kg of broccoli, and 38 comma 900

kg of carrots. how many packages of each style should it prepare to use up existing supplies?

Italian style = 18,000 packages

French style = 14,000 packages

Oriental style = 53,000 packages

Step-by-step explanation:

See the attached figure to represent the question

let the number of packages of Italian style = x

let the number of packages of French style = y

let the number of packages of Oriental style = z

Italian style ⇒ 0.4 kg of zucchini, 0.3 kg of broccoli, and 0.3 kg of carrots.

French style ⇒ 0.5 kg of broccoli and 0.5 kg of carrots.

Oriental style ⇒ 0.2 kg of zucchini, 0.3 kg of broccoli, and 0.5 kg of carrots.

The amount of zucchini ⇒ 17,800 = 0.4x + 0 * y + 0.2z

The amount of broccoli ⇒ 28,300 = 0.3x + 0.5y + 0.3z

The amount of carrots   ⇒ 38,900 = 0.3x + 0.5y + 0.5z

Solving the 3 equations together to find x , y and z

Using the calculator:

x = 18,000 ⇒ Italian style packages

y = 14,000 ⇒ French style packages

z = 53,000 ⇒ Oriental style packages

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step-by-step explanation:

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.