For each sequence, find the first 4 term and the 10th term 2nsquard (algbra) pls can sm1 answer me plis

see explanation

Step-by-step explanation:

To find the terms of the sequence substitute n = 1, 2, 3, 4, 10 into the rule.

n = 1 → 2(1)² = 2(1) = 2

n = 2 → 2(2)² = 2(4) = 8

n = 3 → 2(3)² = 2(9) = 18

n = 4 → 2(4)² = 2(16) = 32

n = 10 → 2(10)² = 2(100) = 200

The first 4 terms are 1, 8, 18, 32 and the 10 th term is 200

2, 8, 18, 32.

10th term =  200.

Step-by-step explanation:

The first 4 terms of 2n^2 are

2(1)^2,  2(2)^2,   2(3)^2, 2(4)^2

= 2, 2*4, 2*9, 2*16

= 2, 8, 18, 32.

The 10th term = 2(10)^2

= 200.

168

step-by-step explanation:

i am pretty sure that the answer is 168

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places