Acat weighs 3.5 ounces when born. the cat grows 0.5 ounces each week. after
how many weeks does the cat way 16.5 ounces?

26 weeks

Step-by-step explanation:

This is an example of an arithmetic sequence.

The first term = 3.5

common difference = 0.5

Using the formula for calculating the nth term of an arithmetic sequence :

= a + (n - 1 ) d

Therefore :

16.5 = 3.5 + ( n - 1 ) x 0.5

16. 5 = 3.5 + 0.5n - 0.5

16.5 = 3 + 0.5n

16.5 - 3 = 0.5n

13.5 = 0.5n

n = 13.5/0.5

n = 27

Therefore , it will take the cat (n-1)  weeks to weigh 16.5 ounce, which will be 27 - 1 = 26

check:

3.5 + 26 ( 0.5)

= 3.5 + 13

= 16.5

answer: i can’t tell you that

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.