The sum of 4 consecutive integers is 18

3 , 4 , 5 and 6

Step-by-step explanation:

Let the consecutive integers be ; x , x+1 , x + 2 and x + 3 , then their sum implies :

x + (x + 1 )  + (x + 2 ) + ( x + 3 ) = 18

x + x + 1 + x + 2 + x + 3 = 18

4x + 6 = 18

4x = 18 - 6

4x = 12

x = 3

Therefore , the numbers are

3 , 3 + 1 , 3 + 2 and 3 + 3

which are :

3 , 4 , 5 , 6

idk

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~