5-14 find an equation of the line that satisfies the given conditions. express the equation in slope-intercept form. 5. slope 3, y- ercept - 2 6. slope y- intercept 4 2/5 7. through (2, - 3) , slope 6 8. through (-3,-5),s] slope a - 7/2 9. through (2, 1) and (1, 6) 10. through (- 1, - 2) and (4, 3) 11. through (4, 84) and (13, - 312) 12. through (6, 70) and (16, 300) 13. x-intercept 1, y- rcept - 3

Slope-intercept form:   y = mx + b   [m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y)]

5. Since you know:

m = 3

b = -2         Plug it into the equation

y = mx + b

y = 3x - 2

6.  Do the same as #5

7. m = 6  and (2, -3)        Plug in m

y = 6x + b      To find b, plug in the point (2, -3)

-3 = 6(2) + b

-3 = 12 + b       Subtract 12 on both sides

-15 = b

y = 6x - 15

8. Do the same as #7

9.  To find the slope, use the slope formula:

      and plug in the two points

(2, 1) = (x₁, y₁)

(1, 6) = (x₂, y₂)

m = -5

y = -5x + b       To find b, plug in either one of the points, I will use (1, 6)

6 = -5(1) + b       Add 5 on both sides

11 = b

y = -5x + 11

10.  Do the same as #9, should be y = x - 1

11.  Do the same as #9 and #10, should be y = -44x + 260

12. Do the same as #9-11, should be y = 23x - 68

13.  x-intercept is the point where the line crosses through the x-axis, or the x value when y = 0 ---> (x, 0)

You know:

x-intercept: (1, 0) and y-intercept: (0, -3)  [(1, 0) is (x₂, y₂)]

Do the same as #9-12 to find the slope

You should get y = 3x - 3

what is all that apply?