Graph the line that has a slope of 1/9 and includes the point (0,8)

Step-by-step explanation:

y = mx + b

slope(m) = 1/9

y int (b) = 8or (0,8)

y = 1/9x + 8this is ur equation

ur x intercept is : (can be found by subbing in 0 for y

0 = 1/9x + 8

-1/9x = 8

x = 8 * -9

x = - 72or (-72,0)

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?