Ayana has 2.35 in nickels and dimes. if she has 33 coins in all, find the number of nickels and dimes.

There are 14 dimes and 19 nickels

Solution:

Let "d" be the number of dimes

Let "n" be the number of nickels

A nickel is worth 5 cents and a dime worth 10 cents

She has 33 coins in all

Therefore, number of dimes + number of nickels = 33

d + n = 33

d = 33 - n ----------- eqn 1

Ayana has 2.35 in nickels and dimes

$ 2.35 is equal to 235 cents

Therefore, we frame a equation as:

number of dimes x 10 cents + number of nickels x 5 cents = 235

10d + 5n = 235 ----------- eqn 2

Substitute eqn 1 in eqn 2

10(33 - n) + 5n = 235

330 - 10n + 5n = 235

5n = 330 - 235

5n = 95

n = 19

Substitute n = 19 in eqn 1

d = 33 - 19

d = 14

Thus there are 14 dimes and 19 nickels

b. astronomers

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions