Of the 420 students enrolled in basic math, only 30% are first year students. how many are first year students? how many are not?

126 are first years and 294 are not.

Step-by-step explanation:

We know that 30% students of 420 students are years. To find the first years we multiply 30% or 0.3 by 420 to get 126.

To find the students who are not first years we take the 420 total students and subtract 126 to get 294 or you can take the remaining 70% or 0.7 of 420 to get 294 which are not the first year students.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form