Consider the vector b⃗ b→b_vec with length 4.00 mm at an angle 23.5∘∘ north of east. what is the y component bybyb_y of this vector?

Explanation:

1. Given vector:

length: 4.00 mm = magnitude of the vectorangle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)

2. y-component

The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.

sine (23.5º) = y-component / magnitudey-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.

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