Icollect a random sample of size n from a population and compute a 95% confidence interval for the proportion i observe from the population. what could i do to produce a new confidence interval with a smaller width, smaller margin of error, based on these same data?

You should increase the size of your random sample, that is, increase the value of n.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is:

This means that as we increase the sample size(n), the margin of error decreases, as does the width of the confidence interval.

What could I do to produce a new confidence interval with a smaller width, smaller margin of error, based on these same data?

You should increase the size of your random sample, that is, increase the value of n.

idk man good luck man

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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step-by-step explanation: