The length of a picture frame is 8 inches more than the width. for what values of x is the perimeter of the picture frame greater than 152 inches.

For, "x" greater than 34, the perimeter of the picture frame greater than 152 inches

Solution:

Let "x" be the width of the frame

Given that, The length of a picture frame is 8 inches more than the width

Therefore,

Length = width + 8

Length = x + 8

The perimeter of rectangle is given by formula:

Perimeter = 2(length + width)

Substituting the values we get,

Perimeter = 2(x + 8 + x)

Perimeter = 2(2x + 8)

Perimeter = 4x + 16

The perimeter of the picture frame greater than 152 inches

Perimeter > 152

Therefore, for, "x" greater than 34, the perimeter of the picture frame greater than 152 inches

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

step-by-step explanation:

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