Find the secant line
y=f(x)=x^2+x
a=-4
b=-1

Step-by-step explanation: Given  is a function as

two values of x are x=-1 and x=2

Corresponding y values are

y(-1) = 1-1 =0 and

y(2) = 4+2 =6

Hence the two points are (-1,0) and (2,6)

Secant line equation can be obtained using two point formula for straight lines

a) Secant line joining (-1,0) and (2,6) is

is the equation of the secant line

b) to find equation of tangent  

Slope of tangent line at (-1,0) = value of derivative at that point

So m =-1 and one point on the line is point of contact (-1,0)

So using point slope formula

step-by-step explanation:

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