At the end of the year, the math club decided to hold an election for which 5 equal officer positions were available. however, 16 candidates were nominated, of whom 7 were past officers. of all possible elections of the officers, how many will have at least 1 of the past officers?

The great thing about this problem is they give you everything you need to solve it easily. so the expression is: 12h+30w12h+30wand so everywhere you have an “h” you place 66. and everywhere you have a “w” you place 33. then the expression will look like this: 12(66)+30(33)12(66)+30(33)from here you multiply and then add. getting the following of: $785,862hope this