Aplastic box 1.5m long, 1.25m wide and 65cm deep is to be made. it is to be open at the top. ignoring the thickness of the plastic sheet, determine i)the area of the sheet required for making the box. ii)the cost of sheet for it, if a sheet measuring 1msquare costs rs.20

(i) The area of the sheet required is 5.45

(ii) Cost of the sheet is Rs 109.

Solution:

Given length of the box (l) = 1.5 m

breadth of the box (b) = 1.25 m

depth of the box (h) = 65 cm = = 0.65 m

Top of the box is open.

(i) To find the area of the sheet required.

Area of the sheet required = Surface area of cuboid – Area of top

                 = 2(lb + bh + lh) – lb

                 = 2(1.5 × 1.25 + 1.25 × 0.65 + 1.5 × 0.65) – (1.5 × 1.25)

                 = 2(1.875 + 0.8125 + 0.975) – 1.875

                 = 2(3.6625) – 1.875

                 = 7.325 – 1.875

                 = 5.45 sq. m

Thus, area of the sheet required is 5.45

(ii) To find the cost of the sheet.

Cost of sheet per 1 = Rs 20

Cost of sheet of 5.45 = Rs (5.45 × 20) = Rs 109

Hence (i) The area of the sheet required is 5.45

          (ii) Cost of the sheet is Rs 109.

you answer is a

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841