Y= 1/(x² + c)
is a one-parameter family of solutions of the first-order de y' + 2xy² = 0.
find a solution of the first-order ivp consisting of this differential equation and the given initial condition. give the largest interval i over which the solution is defined.

Step-by-step explanation:

We are given that one parameter family of solution of the first order DE

DE

Substitute x=2

Substitute the value of c

Solution is defined for all  values of x except x=

Therefore, by unique existence theorem

The largest interval on which the solution is defined

step-by-step explanation:

if x = 2 you have to find x to finish the problem

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°