An area reserved for a parking lot is 80 feet long and 77 feet wide. the stalls of the lot are at 90° angles to two one-way aisles. each aisle is 80 feet by 10 feet. the three areas set aside for the parking spaces are congruent rectangles. each parking space will be 19 feet by 8 feet. what is the maximum number of parking spaces that will fit in the lot?

30 spots

Step-by-step explanation:

Length of parking lot = 80ft

Width of parking lot = 77ft

Lenght of aisle = 80ft

Width of aisle = 10ft

Length of parking space = 19ft

Width of parking space = 8ft

There are two (2) columns which are 10ft wide. So we can walk through an aisle of 2*10 = 20ft width

The width of the parking spots will be 77 - 20 = 57ft

The parking spots are 8ft wide. their width is parallel to the length of the overall lots which is 80ft.

To find the number of times the parking spot is found in the overall lot, we have 80/10 = 10 times

Therefore, we have 10 spots for each row if parking space.

Each spot is 19ft long. To find the number of rows we have 57/19 = 3 rows.

So we have 3 rows by 10 columns

= 3*10 = 30 spots

what is the question?

step-by-step explanation:

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.