In order to solve the system of equations below, harvey multiplies each equation by a constant to eliminate the x terms.

7 x + 3 y = 5. 2 x + 5 y = negative 11.

what are the resulting equations?
14 x + 6 y = 10. negative 14 x minus 35 y = 77.
14 x + 6 y = 10. negative 14 x + 35 y = 77.
14 x + 6 y = 10. negative 14 x minus 35 y = negative 77.
negative 14 x minus 6 y = 10. 14 x + 35 y = negative 77.

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

Step-by-step explanation:

Let's find out the constants to eliminate the x terms

7 x + 3 y = 5

2 x + 5 y = negative 11

Let's multiply the first equation by 2 and the second one by -7, this way:

2 * (7 x + 3 y = 5)

-7 * (2 x + 5 y = negative 11)

14x + 6y = 10

-14x - 35y = 77

The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.