Dave ordered dinner for a party of 10 people. three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each. what was the average cost of each dinner at dave's party?

The average cost of each dinner at Dave's party is $5.79.

Step-by-step explanation:

Given:

Dave ordered dinner for a party of 10 people.

Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.

Now, to find the average cost of each dinner at Dave's party.

So, we get the total amount for the dinner:

Three people ordered the $4.75 chicken dinner.

Two people ordered the $4.95 fish dinner.

Five had the beef dinner at a cost of $6.75.

Total amount of dinner =

Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:

Therefore, the average cost of each dinner at Dave's party is $5.79.

total of apples - take away four

6-4 = 2

answer is 2 apples