Abaseball catcher is performing a stunt for a television commercial. he will catch a baseball (mass 145 g) dropped from a height of 60.0 m above his glove. his glove stops the ball in 0.0100 s. what is the force exerted by his glove on the ball?

174kN

Step-by-step explanation:

F ( force) = mass (m) × acceleration (a)

From equations of motion

h = ut + 1/2at^2

h = 60m, t = 0.01s, u = 0m/s

60 = 1/2×a×0.01^2

a = 60×2/1×10^-4 = 1.2×10^6m/s^2

Mass (m) = 145g = 145/1000 = 0.145kg

F = ma = 0.145×1.2×10^6 = 174000N = 174000/1000 = 174kN

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180