Rectangle a has a length of 80 inches and a width of 30 inches. rectangle a has the same area as rectangle b, but has different dimensions. the width of rectangle b is 80% shorter than the width of rectangle a as shown. which percent represents how much longer the length of rectangle b must be to maintain the same area as rectangle a?

The length of rectangle B must to be 25% greater than the length of rectangle A

Step-by-step explanation:

step 1

Find the area of rectangle A

substitute the given values

step 2

Find the width of rectangle B

Multiply by 0.80 (80%) the width of rectangle A

step 3

Find the length of rectangle B

we have

substitute in the formula of area

solve for L

step 4

Find the percentage

we know that

The length of rectangle A represent 100%

so

using proportion

Find out what percentage represent the difference of its length

100-80=20 in

therefore

The length of rectangle B must to be 25% greater than the length of rectangle A

my guess would be b and d, but i didn’t actually get out the pen and paper. lol