Atheater wants 2000$ and children's tickets cost 5$ and adult tickets cost 10$.what is one combination of children and adult tickets that will make 2000$

Therefore the one  combination is

200 tickets of Children and 100 tickets of Adult.

Therefore Total Amount will be given as

    ..........As Required

Step-by-step explanation:

Given:

Children's tickets cost = 5$ (per ticket)

Adult tickets cost = 10$ (per ticket)

Total Amount = 2000$

Let the number of Children's Ticket be " x "

and the number of Adult's Ticket be " y "

Therefore,

Total cost for Children's Ticket will be =

Total cost for Adult's Ticket will be =

Therefore Total Amount will be given as

     ...........As Required

So there are many combinations to get 2000$ one of the as follow

Children's tickets cost = 1000$

∴

Adult's tickets cost = 1000$

Therefore the one  combination is

200 tickets of Children and 100 tickets of Adult.

One combination would be 100 adults tickets and 200 children tickets.

Step-by-step explanation:

Given:

Cost of children's ticket = $5

Cost of adult's ticket = $10

The theater wants to make $2000

To find one combination of children and adult tickets that will make $2000.

Solution:

Let us assume a combination that:

Total money made from children tickets be = $1000

Total money made by adults tickets will be = = $1000

Thus, number of children's tickets will be:

⇒

⇒

⇒ 200

Thus, number of adult tickets will be:

⇒

⇒

⇒ 100

Thus, one combination would be 100 adults tickets and 200 children tickets.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm