Asap for brainliest: the time required to finish a test in normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. what is the z-score for a student who finishes the test in 23 minutes? show work : )

The z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean of time to finish a test = 60 minutes

Standard deviation of time to finish a test = 10 minutes

Time that a student finishes the test = 23 minutes

2. What is the z-score for the student?

z-score = (Time that a student finishes the test - Mean of time to finish a test)/Standard deviation of time to finish a test

Replacing with the real values:

z-score = (23 -60)/10 = -37/10 = -3.7

z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%

y > 1/3x

y < = -x + 4

hope this : )

answer: - (a)

(b) 88 seats

step-by-step explanation:

given: in an auditorium, there are 22 seats in the first row and 28 seats in the second row.

thus first term=

second term=

the number of seats in a row continues to increase by 6 with each additional row.

⇒d= 6

a) given formula :

b)   let the number of seats (n) = 12

substitute n=12 in the explicit rule formed in (a)

∴there are 88 seats in 12 rows.