The perimeter of ▭pqrs is 84. find the length of each side of ▭pqrs under the given conditions: sp = rs2.
the lengths pq and rs are
the lengths qr and sp are

Step-by-step explanation:

Given,

The perimeter of ▭PQRS = 84

And SP = 2RS

To find, the lengths PQ and RS = ? and

The lengths QR and SP = ?

∴ The perimeter of ▭PQRS = PQ + QR + RS + SP

PQ = RS and QR = SP

The perimeter of ▭PQRS = RS + SP + RS + SP

= 2(RS + SP)

⇒ 2(RS + SP) = 84

⇒ RS + SP = 42

⇒ RS + 2RS = 42

⇒ 3RS = 42

⇒ RS = 14

∴ SP = 2 × 14 = 28

Thus, the lengths PQ and RS are 14 units and The lengths QR and SP are 28 units.

write out the polynomial, with leading coefficient 1:

y = 1 (x+2)^1 (x-7)^1 (x-5)^2

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