Solve the following problems AND show your work. Only hand written answers will be excepted!

1. What are the volumes of m
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2. Mr. Bernard need to order boxes for his 16 inch diameter “super pizza.”

A. Why is the approximate circumference of the “super pizza? Use 3.14 for π. Do not run your answer!
Use the correct label. Show work.

B. What is the approximate area of the super pizza? Use 3.14 for π. Do not round your answer! Use the correct label. Show your work.

C. If he sellsthe pizza for $0.18 per square inch, what is the total cost of his pizza? Show your work.

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people

1. minimum

2. 6400

3. eight

hope this !

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.