Use a system of equations to solve this problem. Bronze is a mix, or alloy, of tin and copper. A metal worker needs 100 g of bronze that is 25% tin. He has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin. Let x = the number of grams of the 5% tin alloy. Let y = the number of grams of the 45% tin alloy. How many grams of each alloy should the metal worker combine?Enter your answers into the boxes.__g of the 5% tin alloy and __g of the 45% tin alloy.

x = 50 grs

y = 50 grs

Step-by-step explanation:

" x "   is quantity of bronze of 5% tin

" y "   is quantity of bronze of 45% tin

The worker needs 100 grs of bronze and this bronze must be 25% tin

The mathematical expression for the 100 grs condition is:

x + y = 100

And the The mathematical expression for the % condition is:

0,05*x  + 0.45*y  = 0,25 * ( x + y )

The system is:

x + y = 100

0,05*x + 0,45*y = 0,25* ( x + y )

Solving this system we get values of x and y

y = 100 - x

0,05*x  + 0,45* ( 100 - x ) = 0,25 * ( x + 100 - x )

0,05*x  + 45 - 0,45*x = 0,25*( 100 )

0,05*x  + 45 - 0,45*x  = 25

- 0,4*x  = -45 + 25

x = 20/0,4            x = 50  grs

and y = 50 grs

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

here is your mark brainliest