When opening a door, you push on it perpendicularly with a force of 55.0 N at a distance of 0.850m from the hinges. What torque are you exerting relative to the hinges? Does it matter if you push at the same height as the hinges?

T=46.75 N-m

No, It does not matter if you push at the same height as the hinges.

Step-by-step explanation:

The formula for Torque is:

T=rxF

T=rFsinθ

where

T is the torque

r is the distance from which force is applied

F is the force to applied

Since,F=55 N, r=0.850 m

Force is acting perpendicular,θ=90 degree

T=rFsin90

T=r*F

T=0.850*55

T=46.75 N-m

According to the formula of Torque:

T=rFsinθ

Torque depends on angle θ and perpendicular distance from point of application of force to the rotation axis, not on the height from which force is applied. So it does not matter if you push at the same height as the hinges.

idk the answer but just put a

step-by-step explanation:

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.