Find the values of r1 and d for an arithmetic sequence r6 = 4 and r8= 5

  a. r1 = 3/2; d = 1/2

Step-by-step explanation:

You can use your number sense to solve this.

Terms r6 and r8 are two terms apart, so their difference will be 2 times the common difference:

  d = (r8 -r6)/2 = (5 -4)/2 = 1/2 . . . . . matches choices A and D

The given terms are even terms. Odd terms will be 'something and 1/2'. The first term of the sequence (n=1) is an odd term, so cannot be 1 (choice D). The only viable answer choice is A.

If you want to solve for r1, use the equation for the general term and put in the numbers for either r6 or r8. (We'll use r6.)

  rn = r1 +d(n -1)

  r6 = r1 +(1/2)(6 -1) = 4

  r1 = 4 -5/2 = 3/2 . . . . matches choice A

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480