It takes of heat to raise the temperature of Object A by , and to raise the temperature of Object B by . Suppose A and B are brought into contact. A is initially hotter. A is seen to cool down by . How would you calculate the rise in temperature of B?

ΔT'  = 9.5 x C / C'

= 4.65°C

Step-by-step explanation:

To calculate the rise in temperature of B, we know that the heat released by Object A will be equal to the absorbed heat by object B

Hence:

Heat released by A = Heat absorbed by B

This means that C ΔT = C' ΔT'

But we are told that when brought into contact, A cools down by 9.5°C, hence we know that the change in temperature by object A is by 9.5°C

Hence:

C ×  9.5 = C' ΔT'

If we make ΔT', which will imply the rise in temperature of B the subject of the formula, we get:

ΔT'  = 9.5 x C / C'

From the question

C = 2.28J

C' = 4.66 J

Hence ΔT' = 9.5 x 2.28/4.66 = 4.65°C

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