Determine the values of r for which the given differential equation has solutions of the form y = tr for t > 0. (Enter your answers as a comma-separated list.) t2y'' + 6ty' + 6y = 0

r= [ -2, -3 ]

Step-by-step explanation:

for

y= t^r

then

y'  =r*t^(r-1)

y''= r*(r-1)*t^(r-2)

thus if

t²y'' + 6t*y' + 6y = 0

r*(r-1)*t^(r-2) * t² + 6*t*r*t^(r-1) + 6*t^r = 0

t^r *[ r(r-1) + 6*r + 6 ] =0

since t>0 , then [ r(r-1) + 6*r + 6 ] =0

r(r-1) + 6*r + 6 =0

r² - r + 6*r + 6 = 0

r²  + 5*r + 6 = 0

r₁,r₂ = [-5 ±√(5² - 4*1*6)]/2*1  

r₁ = (-5+1)/2 = -2

r₂ = (-5-1)/2 = -3

then r= [ -2, -3 ]

answer with step-by-step explanation:

a. ∠j is supplementary to ∠k - true:

(opposite angles of a trapezoid are supplementary which means that they add up to 180 degrees)

b. kl is parallel to jm - true:

(opposite sides are parallel to each other in a trapezoid)

c. jk is perpendicular to kl - false:

(clearly, jk does not make a right angle with kl)

d. jk is parallel to lm - false:

(jk and lm are two lines opposite in direction to each other so they cannot be parallel)

e. ∠j is congruent to ∠m - true:

(the angles on each side of the base are congruent)

f. ∠j is congruent to ∠k - false:

(the angles on the same side but opposite side of the base are not congruent)