Find the solution for this system of equations.
2x + 4y = 8
x = 3y - 6

x = 0 , y = 2

Step-by-step explanation:

Solve the following system:

{2 x + 4 y = 8 | (equation 1)

x = 3 y - 6 | (equation 2)

Express the system in standard form:

{2 x + 4 y = 8 | (equation 1)

x - 3 y = -6 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 4 y = 8 | (equation 1)

0 x - 5 y = -10 | (equation 2)

Divide equation 1 by 2:

{x + 2 y = 4 | (equation 1)

0 x - 5 y = -10 | (equation 2)

Divide equation 2 by -5:

{x + 2 y = 4 | (equation 1)

0 x+y = 2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{x+0 y = 0 | (equation 1)

0 x+y = 2 | (equation 2)

Collect results:

{x = 0 , y = 2

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