The length of a rectangle is three times it's width. If the width is diminished by 1 m and length is increased by 3 m, the area of the rectangle that is formed is 72 m². Find the dimensions of the original rectangle.

the length is 15 m and the width is 5 m

Step-by-step explanation:

Let L represent the original length of the rectangle.

Let W represent the original width of the rectangle.

The length of a rectangle is three times it's width. This means that

L = 3W

If the width is diminished by 1 m and length is increased by 3 m, the area of the rectangle that is formed is 72 m². This means that

(L + 3)(W - 1) = 72

LW - L + 3W - 3 - 72 = 72 + 3

LW - L + 3W = 75 - - - - -- - - - - - 1

Substituting L = 3W into equation 1, it becomes

3W × W - 3W + 3W = 75

3W² = 75

W² = 75/3 = 25

W = √25 = ±5

The width cannot be negative. Therefore, the width is 5 m

L = 3W = 3 × 5 = 15 m

step-by-step explanation:

a and d

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5