1.
How is the graph of y = 3x + 2 different from the graph of y = 3x??

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]

y = 3x + 2        m = 3     b = 2

y = 3x              m = 3      b = 0

y = 3x + 2 is different from the graph of y = 3x because it has a y-intercept of 2, while the y-intercept of y = 3x is at the origin (0, 0)

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step-by-step explanation:

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