Consider the sets of vectors of the following form. Determine whether the sets are subspaces of R3. If a set is a subspace, give a basis and its dimension. (Enter your basis as a comma-separated list. Enter each vector in the form (x1, x2, ...). If a set is not a subspace, enter NA for its basis and dimension.)
How do I go about this last one?
(c) (a, b, 4) basis NA dimension NA
(d) (a, a, a + 5) (1.16)x basis dimension1

step-by-step explanation:

hjkj

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1