A surveyor standing at point A sights two targets, one at B and one at C. He measures that target [5 pts] B is 87 yards away, target C is 459 yards away and the angle between them is 41 degrees. Use solve and the Law of Cosines to find the distance between B and C. Assign to p10. Note: Using solve applied directly to the LOC will yield both a positive and negative solution - please do this. And how to code in mathlab

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

$54.99

step-by-step explanation:

$54.99 includes 500 min. if she does not exceed 500 min then her bill is $54.99

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w

answer: correct

step-by-step explanation: