The fill weight of a certain brand of adult cereal is normally distributed with a mean of 910 grams and a standard deviation of 5 grams.

If we select one box of cereal at random from this population, what is the probability that it will weigh less than 900 grams?
0.0228 T/F

p = 0.02275

Step-by-step explanation:

Given

μ = 910 g

σ = 5 g

x = 900 g

We can use the equation

Z = (x - μ)/σ   ⇒    Z = (900 g - 910 g)/5 g = - 2

using the table (with Z = -2) we get

p = 0.02275

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