A sample consisting of four pieces of luggage was selected from among those checked at an airline counter, yielding the following data on x = weight (in pounds). x1 = 33.2, x2 = 27.6, x3 = 36.9, x4 = 30.7 Suppose that one more piece is selected and denote its weight by x5. Find all possible values of x5 such that x = sample median. (Enter your answers as a comma-separated list.)

x5 = 25.1 lb, 32.1 lb, 37.6 lb.

Step-by-step explanation:

The sum of the weight of the four given luggages is:

We want to find a value for x5 that yields a sample mean equal to the sample median.

Assuming x1 = 33.2 as the median:

Assuming x4 = 30.7 as the median:

Assuming x5 as the median:

x2 and x3 cannot be the median since they are the lowest and highest value in the set, respectively.

All possible values are x5 = 25.1 lb, 32.1 lb, 37.6 lb.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3