Two cards are chosen from a pack of cards without replacement. Calculate the probabilities: (a) Both are picture cards. (b) Both are from red suits. (c) One card is from a red suit and one card is from a black suit.

A) 0.0498

B)0.2451

C) 0.2549

Step-by-step explanation:

Total number of cards N = 52

A) Number of picture cards including the king, Queen ,jack = 12

P(picture cards) = (12/52)*(11/51)

P(picture cards) = 0.0498

B) Number of red cards ( hearts and diamonds) = 26

P( red cards) = (26/52)*(25/51)

P(red cards) = 0.2451

C) Number of black cards ( Spaders and clubs) = 26

P( one red and one black cards) = (26/52)*(26/51) = 0.2549

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

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