Of all the permutations of the letters in the word DOG, if you choose one at random, what is the probability that it is an actual English word?

1/3

Step-by-step explanation:

Total letters in DOG = 3

All possible permutations = 3! = 6

Words are DOG, GOD, OGD, ODG, DGO, GDO

Actual English words = 2 out of 6

Probability that it is an actual English word = 2/6 = 1/3

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: