Wade wanted to make a model where a shot. Was taken during an nba game 1cm=2 feet if a shot was taken around half court at 47 feet how many centimeters would that be on the model

  23.5 cm

Step-by-step explanation:

The model distance x is proportional to the scale:

  x/(47 ft) = 1 cm/(2 ft)

Multiplying by 47 ft gives ...

  x = (1 cm)(47/2) = 23.5 cm

The distance from half-court on the model is 23.5 cm.

23.5cm

Step-by-step explanation:

From the question,

1cm =2feet

Xcm = 47feet

Cross multiply

Xcm x 2 = 47x1

Divide both sides by 2

Xcm = 47/2

= 23.5cm

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.