A right triangle has a hypotenuse of 10 mi. and a leg of 6 mi., what is the length of the other leg?

8mi

Step-by-step explanation:

Using Pythagoras theorem

Hypotenuse square = opposite square + adjacent square.

Let the other leg be x

10 square = 6 square + x square

100 = 36 + x square

Collect like terms

X square = 100 -36

X square = 64

Find square root of both sides

X = square root of 64

X =8mi

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(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1

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