A number is selected at random from the set {1,2,3,…,1000}. What is the probability that it is divisible by 19?

the probability is %5.2

Step-by-step explanation:

To know the probability that it is a multiple of 19 we have to know the number of multiples that 19 has between 1 and 1000. And that amount divide it by 1000. Finally we multiply it by 100 and we will have the percentage.

To know how many multiples there are from 1 to 1000 we have to make 1000 divided by 19 and the number that we get the decimals.

1000/19 = 52.63

there are 52 multiples

100*52/1000 = 5.2

the probability is %5.2

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

83-45=38

38 was the other number

hope your goes well, here's a turkey

-thekoolkid1o1