Help with this question

x = 4, y = 6

Step-by-step explanation:

∠ DEC = 112° ( vertical angle )

Since BE = CE then Δ BCE is isosceles

∠ BCE = 7x + 6 ( base angles of an isosceles Δ are congruent )

The sum of the 3 angles in a triangle = 180°, thus

112 + 7x + 6 + 7x + 6 = 180, that is

14x + 124 = 180 ( subtract 124 from both sides )

14x = 56 ( divide both sides by 14 )

x = 4

∠ DEC = 180° - 112° = 68° ( straight angle )

Since CE= DE then Δ CDE is isosceles

∠ DCE = 9y + 2 ( base angles of an isosceles Δ are congruent )

The sum of the 3 angles = 180°, thus

68 + 9y + 2 + 9y + 2 = 180, that is

18y + 72 = 180 ( subtract 72 from both sides )

18y = 108 ( divide both sides by 18 )

y = 6

answer: it's d

step-by-step explanation:

30,40,50 is correct answer